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md5加密算法C++程序

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发表于 2004-11-26 20:11:20 | 显示全部楼层 |阅读模式
#include "global.h"
: N4 o/ k/ R, N$ a #include "md5.h"
) H5 q7 R, d9 O1 ^+ s
: z& q2 c& }5 n2 ?, t% f8 Y) U K /* Constants for MD5Transform routine.
*/
) J$ |, Q+ F' B
3 v6 o5 x, h1 n" b2 r( _
) g& A* o7 A2 c#define S11 7
3 r! R9 g& o" }% Y0 K& B% \ #define S12 12
s. j P, p" i | d, Q #define S13 17
+ \; N$ \" v; f/ y z#define S14 22
& @! T+ l$ r6 H$ p% z* d; `5 v #define S21 5
- J% F7 G( v5 {- k; w7 b. c6 B f1 `#define S22 9
# \+ U9 b) v; T' r7 Y! b#define S23 14
2 c$ \8 |# D0 N#define S24 20
/ h# [3 h5 r& | #define S31 4
$ Y+ M% M8 T* N, B: i5 J #define S32 11
; G% o" ^2 ^) a* C: A9 t9 k #define S33 16
" h1 [- S, k c: ~4 L" A. t#define S34 23
" T) V) N! l7 j/ ^2 L, w #define S41 6
7 z+ c+ [! k0 I# ? #define S42 10
5 h, [4 `& o$ Z. f7 Z) b #define S43 15
2 R3 v. M) E1 b0 Q! Q8 M; _# `#define S44 21
( U' ~) u/ q) o4 g, H0 A
. J- v* U2 M& K, Ostatic void MD5Transform PROTO_LIST ((UINT4 [4], unsigned char [64]));
9 H# ]9 A& O P' g static void Encode PROTO_LIST
((unsigned char *, UINT4 *, unsigned int));
5 W% C/ g9 H0 h- a o static void Decode PROTO_LIST
((UINT4 *, unsigned char *, unsigned int));
/ ~9 _5 [: v( p& E static void MD5_memcpy PROTO_LIST ((POINTER, POINTER, unsigned int));
5 [( R# F% i4 w/ o" X/ b6 rstatic void MD5_memset PROTO_LIST ((POINTER, int, unsigned int));
% Z/ p7 z* t2 Y& |/ x9 i
2 s# R0 s% ^3 ]static unsigned char PADDING[64] = {
0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
& X, {/ F5 ^# |' ~ };
* \ w" R: l1 F. G) F7 S
7 P9 n6 A' {% p$ B3 h8 P3 w/* F, G, H and I are basic MD5 functions.
*/
: o5 e; E" `. ?( V: k #define F(x, y, z) (((x) & (y)) | ((~x) & (z)))
% _; O; w7 [* N$ B( d#define G(x, y, z) (((x) & (z)) | ((y) & (~z)))
+ x4 |% p% e6 v2 E6 v#define H(x, y, z) ((x) ^ (y) ^ (z))
+ ]- y7 Y+ P9 ]#define I(x, y, z) ((y) ^ ((x) | (~z)))
; S8 B- }/ T/ y# }' H2 J8 I0 n
( @5 v6 }" N1 J3 g7 z* i( {/* ROTATE_LEFT rotates x left n bits.
*/
, c3 A- M6 [0 V9 m' f* Y. O* E) A#define ROTATE_LEFT(x, n) (((x) << (n)) | ((x) >> (32-(n))))
; S; L- D$ I( W6 N6 K
. m; ?# U: i5 G8 e& |3 {1 }0 Q; L/* FF, GG, HH, and II transformations for rounds 1, 2, 3, and 4.
. n8 G8 S0 e- j; c* C/ X. ^Rotation is separate from addition to prevent recomputation.
*/
9 o* T- e" ^1 d1 r) L #define FF(a, b, c, d, x, s, ac) { \
(a) += F ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
/ ^& j8 Z" x1 B! y7 Y #define GG(a, b, c, d, x, s, ac) { \
(a) += G ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
" K. w% u. |* W2 b1 [ i" s#define HH(a, b, c, d, x, s, ac) { \
(a) += H ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
7 X+ C' c* }! {2 B# s4 G7 @$ y #define II(a, b, c, d, x, s, ac) { \
(a) += I ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
, V4 s8 X9 Z6 L& _% A5 A3 r. [$ p4 |
4 r% O1 T g7 m, J3 S/* MD5 initialization. Begins an MD5 operation, writing a new context.
*/
7 K" v! S2 C( Z/ Avoid MD5Init (context)
! B8 |- m6 y9 ` v2 F MD5_CTX *context; /* context */
' h. o/ e2 P, a{
context->count[0] = context->count[1] = 0;
/* Load magic initialization constants.
/ ~: r% v) n6 Z; X9 m*/
context->state[0] = 0x67452301;
context->state[1] = 0xefcdab89;
context->state[2] = 0x98badcfe;
context->state[3] = 0x10325476;
3 }4 P% B# \( h p' R& ~ }
2 a+ s9 d ^7 q$ K) m# m+ W" V; z, Q0 p" z
4 Z1 {/ B& q1 ]% L. z5 j E2 i+ F/* MD5 block update operation. Continues an MD5 message-digest
operation, processing another message block, and updating the
context.
*/
- f# x* N1 J. t+ R5 \9 nvoid MD5Update (context, input, inputLen)
5 Z1 n+ ~1 d+ E9 y7 n$ W MD5_CTX *context; /* context */
4 j) m3 w9 i& L) Z. f* c! E$ I# ` unsigned char *input; /* input block */
; q/ R2 K+ r8 Q3 D0 c2 R8 } unsigned int inputLen; /* length of input block */
5 N+ m6 Y9 D; K {
unsigned int i, index, partLen;
6 K* v( Q1 e& g& D* C, K
/* Compute number of bytes mod 64 */
index = (unsigned int)((context->count[0] >> 3) & 0x3F);
7 f/ _; N5 }+ Y8 A: G2 l
/* Update number of bits */
if ((context->count[0] += ((UINT4)inputLen << 3))
&
不在競爭中變坏,就在沉默中變態

安防知名大师

探花

Rank: 7Rank: 7Rank: 7

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发表于 2004-11-26 20:22:48 | 显示全部楼层

md5加密算法C++程序


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6 A# z4 o5 k* M. P- I
guoyun786@sohu.com
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